[Stoves] Variable Speed Stove Fan SIMPLIFIED

[Kevin Chisholm]

Dear Jeff

1 Watt = .101 kilogram-meter per second

Assuming 100% efficiency of your turbine, then for each watt of fan power, 
you will require .101 kg of water to fall through 1 meter.

If the waterwheel efficiency was 50%, then you would need .202 kg of water 
flow per second for each watt of shaft power output to the fan. Each minute 
would require about 12 kG water flow; each hour will require lifting about 
720 kG of water a distance of 1 meter

If you require 3 watts of power to drive your fan, you would need to lift 
about 2160 kG water per hour.

The system would work, but it would be tedious.

Best wishes,

Kevin
----- Original Message ----- 
From: "Jeff Davis" <jeff0124 at velocity.net>
To: "Discussion of biomass cooking stoves" <stoves at listserv.repp.org>
Sent: Monday, December 04, 2006 8:20 PM
Subject: Re: [Stoves] Variable Speed Stove Fan SIMPLIFIED


> Dear List,
>
> The idea of a simplified speed control hit's home: In regards to the
> HydoFan (water wheel fan), I was going to use a valve to control the
> water/fan speed, but with all this talk, the idea struck me to just place
> the water container on a higher self for hi speed. That's if the HydroFan
> will work at all.
>
>
> Best regards,
>
> Jeff
>
>
>
> -- 
> Jeff Davis
>
> Some where 20 miles south of Lake Erie, USA
>
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