[Stoves] Variable Speed Stove Fan SIMPLIFIED

[Jeff Davis]

Hi Kevin,

Yes, I've been doing some of the math with Hp (33,000/ft) and I agree it
adds up to a lot of water being lifted.

Just a few watts add up to a huge amount of work! In our modern world, how
do we ever generate all this energy.............


Jeff

Kevin wrote:
> 1 Watt = .101 kilogram-meter per second
>
> Assuming 100% efficiency of your turbine, then for each watt of fan power,
> you will require .101 kg of water to fall through 1 meter.
>
> If the waterwheel efficiency was 50%, then you would need .202 kg of water
> flow per second for each watt of shaft power output to the fan. Each
> minute
> would require about 12 kG water flow; each hour will require lifting about
> 720 kG of water a distance of 1 meter
>
> If you require 3 watts of power to drive your fan, you would need to lift
> about 2160 kG water per hour.
>
> The system would work, but it would be tedious.
>
> Best wishes,
>


-- 
Jeff Davis

Some where 20 miles south of Lake Erie, USA