[Stoves] Using a differential windlass as motive power for stove

[Steve Taylor]

Boll, Martin Dr. wrote:
> Turn the calculation and ask if you could lever a weight of 540 kg a 2meter
> high distance with an electrical motor, having a mechanical output power of
> 3 Watt.
>
> I did not calculate that, but I have the feeling that it does not work.
>
>   
Of course it "works". How could it possibly not do ? Really, we have 
little feel for the amount of power we consume and can create.

Here is some more simple math.
Weigh yourself. (M kg)
Measure the height of a flight of stairs.(h, metres)
Climb it, (walk) and time your climb.(t , seconds )
Apologies to non-metric readers.

Now At the top of the stairs, you have gained Mgh Joules of energy. You 
acquired these in t seconds . Your power output is Mgh/t Watts.
Now, go down again, and RUN up the stairs absolutely as fast as you can. 
You will be very lucky to sustain as much as 600 Watts. After 20 seconds 
at that output you will be pretty tired !

Makes you think doesn't it ?

> Imagine: 
>
> -The drive of an old feet-driven sewing-machine would drive a small flywheel
> connected -in the right gear- with a small radial-fan (instead of a
> sewing-machine). That would certainly work, and if not, 
>
> -you could use a sort exercise machine (bicycle-type) to generate even more
> energy than needed.
>
> By each of these two things, I think, you could manage the 540Kg being
> lifted 2m within 2 hours.
>
>   

Why mess about, and compound inefficiency. Use the pedal to power the 
fan directly. But no transmission is lossless.

Steve