[Stoves] [Fwd: Superficial Velocities of Power gasifiers and WoodGas Stoves]

[Crispin Pemberton-Pigott]

Dear Frank

....Flow was constant at 0.5 LPM.

....It took about 18 seconds without the 'fuel' 
and about 56 seconds with the 'fuel' 

So roughly 1/2 the space was full and it increased the time needed by a
factor of 3.

If you were to take a standard air flow formula and calculate the reduction
in flow for a 50% reduction in area (assuming it is not a formula for a
shaped injector or something efficient) would you expect a similar result?

But...if the flow was constant at 0.5 LPM, how could it have taken longer?
Was the flow 0.5 without no 'fuel' and less without it?  Was it perhaps
constant pressure that gave a flow of 0.5 without fuel?

Thanks
Crispin